3(3x+7/5)=9^x

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Solution for 3(3x+7/5)=9^x equation: 



3(3x+7/5)=9^x

We move all terms to the left:

3(3x+7/5)-(9^x)=0

We add all the numbers together, and all the variables

3(+3x+7/5)-9^x=0

We multiply parentheses

9x-9^x+7/5*3=0

We multiply all the terms by the denominator


9x*5*3-9^x*5*3+7=0

Wy multiply elements

135x*3-135x*3+7=0

Wy multiply elements

405x-405x+7=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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